PAT甲级1150题（旅行商）

1.题目介绍

2.考察点，难度

散列类，Vector容器自定义方法，Set容器的运用，难度中

3.解题代码

#include <iostream>
#include <vector>
#include <set>
using namespace std;
int e[300][300], n, m, k, ans = 99999999, ansid;
vector<int> v;

void check(int index) {
    int sum = 0, cnt, flag = 1;
    scanf("%d", &cnt);
    set<int> s;
    vector<int> v(cnt);
    for (int i = 0; i < cnt; i++) {
        scanf("%d", &v[i]);
        s.insert(v[i]);
    }
    for (int i = 0; i < cnt - 1; i++) {
        if(e[v[i]][v[i+1]] == 0) flag = 0;
        sum += e[v[i]][v[i+1]];
    }
    if (flag == 0) {
        printf("Path %d: NA (Not a TS cycle)\n", index);
    } else if(v[0] != v[cnt-1] || s.size() != n) {
        printf("Path %d: %d (Not a TS cycle)\n", index, sum);
    } else if(cnt != n + 1) {
        printf("Path %d: %d (TS cycle)\n", index, sum);
        if (sum < ans) {
            ans = sum;
            ansid = index;
        }
    } else {
        printf("Path %d: %d (TS simple cycle)\n", index, sum);
        if (sum < ans) {
            ans = sum;
            ansid = index;
        }
    }
}
int main() {
    scanf("%d%d", &n, &m);
    for (int i = 0; i < m; i++) {
        int t1, t2, t;
        scanf("%d%d%d", &t1, &t2, &t);
        e[t1][t2] = e[t2][t1] = t;
    }
    scanf("%d", &k);
    for (int i = 1; i <= k; i++) check(i);
    printf("Shortest Dist(%d) = %d\n", ansid, ans);
    return 0;
}

4.原题地址

https://pintia.cn/problem-sets/994805342720868352/problems/1038430013544464384