1.题目介绍
2.考察点,难度
字符串处理类,string的遍历,string个别位置替换,难度易
3.解题代码
#include <bits/stdc++.h>
using namespace std;
int main(){
freopen("D:\\PAT\\Clion\\in.txt","r",stdin);
int N,sum=0,flag=0;
cin>>N;
vector<string> va,vb;
for(int i=0;i<N;i++){
string a,b;
cin>>a>>b;
for(int j=0;j<b.length();j++){
if(b[j]=='1') {
b[j]='@',flag=1;
}
if(b[j]=='0') {
b[j]='%',flag=1;
}
if(b[j]=='l') {
b[j]='L',flag=1;
}
if(b[j]=='O') {
b[j]='o',flag=1;
}
}
if(flag){
va.push_back(a);
vb.push_back(b);
sum++;
flag=0;
}
}
if(!sum) N==1?cout<<"There is 1 account and no account is modified"<<endl:cout<<"There are "<<N<<" accounts and no account is modified"<<endl;
else{
cout<<sum<<endl;
for(int i=0;i<va.size();i++){
cout<<va[i]<<" "<<vb[i]<<endl;
}
}
return 0;
}
4.原题地址
https://pintia.cn/problem-sets/994805342720868352/problems/994805454989803520